What is the slope of the tangent line passing through the point (2, 3) of the graph of this function?
f(x) = x2 + 2x − 5
1
2
3
4
6
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OpenStudy (michele_laino):
hint:
we have to compute the first derivative of f(x) at point x=2
OpenStudy (anonymous):
f(x) =3
OpenStudy (michele_laino):
no, we have to compute the first derivative of f(x):
\[f'\left( x \right) = ...?\]
OpenStudy (michele_laino):
hint:
the first derivative of x^ is 2*x
and the first derivative of x, is 1
OpenStudy (michele_laino):
oops..x^2
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OpenStudy (anonymous):
x^ is x^2?
OpenStudy (michele_laino):
yes!
OpenStudy (michele_laino):
so the first derivative of f(x), is equal to
the first derivative of x^2 plus the first derivative of 2x
please note that the first derivative of -5 is zero
OpenStudy (anonymous):
so its 1
OpenStudy (michele_laino):
the first derivative of f(x), is:
f ' (x)=2x+2
so, what is f ' (2)=...?
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OpenStudy (michele_laino):
f ' (2) = 2*2+2=...?
OpenStudy (anonymous):
6
OpenStudy (michele_laino):
that's right!
OpenStudy (anonymous):
ok I had got 6 but I was second guessing got confused
OpenStudy (anonymous):
thanks
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