A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could possibly receive the tickets?

Question

anonymous · Answer

Is it only by gender or is each friend counted to be different?

anonymous · Answer

it's by each friend counted to b different

joel_the_boss · Answer

Welcome to openstudy.

joel_the_boss · Answer

Have you attempted to find combinations? Or would you like me to show you?

alekos · Answer

C (8, 5)

anonymous · Answer

SO, Order does not matter here. By this I mean it doesn't matter who gets picked first. The 5 lucky kids might be ABCDE, or ACBDE, that's the same 5. So this is a combination.

anonymous · Answer

so it should be 8C5 which means 8!/[(8-5)!(5)!].
simplifying further gives you 56 possible combos