Question

Am I factoring this correctly? I've not done this since middle school heh.

Answer 1

\[x ^{3}+x=x ^{2}(x+1)\] or can I factor it even more?

Answer 2

You can't factor \(x^2\) out since the last term is only an x

Answer 3

Oh I meant it otherwise, let me edit it

Answer 4

\[x ^{3}+x=x(x ^{2}+1)\]

Answer 5

yep :)

Answer 6

Can I factor it even more, or that's as far as it goes? and I got other 9 of these, how do I know if I've reached the most simple form?

Answer 7

That would be as far as that one goes

Answer 8

if the original had been something like \(2x^2 + 6x\), then you could factor out 2 and x to make \(2x(x^2+3)\)

Answer 9

and how would I know if it's on it simplest form? I know this is a middleschool question, but I can't remember and I need this for integrating heh, currently in college.

Answer 10

What about this one:
\[(x-1)(x ^{2}+x+1)\]

Answer 11

Is that already factored or you have to factor it?

Answer 12

you cannot factor that in the domain of real numbers. As long as the square inside bracket has no solution (negative discriminant), it is unfactorable.

Answer 13

That's the equation that I'm given, so I can't factor that?

Answer 14

Discriminant of the square you posted is -3, therefore you cannot factor it.

Answer 15

I see, I'm learning alot from you 2 :p