Question

help

Answer 1

Simplify 5 log2 k –8 log2 m + 10 log2 n.

Answer 2

@Michele_Laino

Answer 3

here we can write this:
\[\Large \begin{gathered}
5{\log _2}k = {\log _2}{k^5} \hfill \\
8{\log _2}m = {\log _2}{m^8} \hfill \\
10{\log _2}n = {\log _2}{n^{10}} \hfill \\
\end{gathered} \]

Answer 4

7 log2 kn/m right answer check

Answer 5

I think that it is not the right answer

Answer 6

no it's right check

Answer 7

sorry, if I apply the properties of logarithm, I get:
\[\Large {\log _2}\left( {\frac{{{k^5}{n^{10}}}}{{{m^8}}}} \right)\]

Answer 8

are you sure

Answer 9

yes!
since I have applied these properties:
\[\Large \begin{gathered}
{\log _2}a + {\log _2}b = {\log _2}\left( {ab} \right) \hfill \\
{\log _2}a - {\log _2}b = {\log _2}\left( {\frac{a}{b}} \right) \hfill \\
\end{gathered} \]

Answer 10

i see what you did there
you can't combine 5 -8 +10 <--- wrong
apply log properties

Answer 11

ok fine thank

Answer 12

Solve 2 log x = log 64.

Answer 13

is x+-8 check right

Answer 14

here we have to apply this property:
\[2\log x = \log {x^2}\]

Answer 15

then x = 32 is right check

Answer 16

we can write:
\[\log {x^2} = \log 64\]

Answer 17

and finally, using the uniqueness of logarithm, we can write:
\[{x^2} = 64\]
so what is x?

Answer 18

8

Answer 19

and -8?

Answer 20

±8

Answer 21

right or wrong

Answer 22

no, -8 it can not be a solution, since x has to be positive for the existence of the logarithm at left side of your equation

Answer 23

8 is answer

Answer 24

yes! it is the unique solution

Answer 25

yes good