Find tanx=3cosx for all answers from [0,2pi)
try writing tan x = sin x / cos x
Welcome!
sin x / cos x = 3 cos x 3 cos ^2 x = sin x now use the identity cos^x = 1 - sin^2x - substitute for cos^2 x to get an equation only in sin x
I got the equation down to 3sin^2(x)+sin(x)-3=0 and used the quadratic equation. The result was( -1+- sqrt(37))/6. Does that seem correct?
so we get 3( 1 - sin^2 x 0 = sin x 3 - 3sin^2 x = sin x 3sin^2 x + sin x - 3 = 0 solve this
your equation was correct
Now that I have this answer, how would I put it in terms of pi/radian form?
yes that solution for sin x looks good
well work the values out on a calculator first they come to 0.8471 and - 1.18 i would just give the answers as radians in decimal form note that 2pi = 6.283
Thank you very much, this has been a huge help!
yw bro
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