Question

solve for k: f=g-h+k/7

Answer 1

any ideas?

Answer 2

no

Answer 3

\[f=g-h+\frac{ k }{ 7 }\]
^
Is this what your problem looks like?

Answer 4

use the idea of "balance"

Answer 5

7 is divide by all three

Answer 6

\(f=\dfrac{g-h+k}{7} \)

Answer 7

what you do to one side of the equation you must do the same to the other to keep it balanced

Answer 8

yes

Answer 9

ah okay

Answer 10

i know skull but im lost on the first part

Answer 11

remember, what is the inverse of division
^
kind of feeds into the whole "balance" idea

Answer 12

so g/7 -h/7+k/7

Answer 13

the change it around

Answer 14

You can't do anything to g, h or k because they are all being divided by 7.
The first step is to get rid of the division by 7 on the right side.
The opposite operation to division is multiplication, so multiply both sides by 7.

Answer 15

basically, we're asking you what you need to multiply by in order to get rid of the denominator

Answer 16

which you do by multiplying both sides by 7. lel you beat me @mathstudent55 ;-;

Answer 17

ok so 7*f=g-h+k

Answer 18

Yes^

Answer 19

\(7 \times f=7 \times \left( \dfrac{g-h+k}{7} \right) \)

\(7f = g - h + k\)

Answer 20

Good.

Answer 21

then -g+h-k

Answer 22

now subtract g from both sides

Answer 23

7*f/h-g-k

Answer 24

Now look at the right side.
Anything that is being added to k, subtract from both sides.
Anything that is being subtracted from k, add to both sides.

Answer 25

yeah i got that part thank you

Answer 26

\(7f = g - h + k\)

\(7f = k + g - h\)

Answer 27

If I may add, you know how you have the order of operations? We shorten it to PEMDAS. In order to solve for something, we reverse it and use SadMep :( <--Gotta have the frowny face :)

Answer 28

\(7f \color{red}{-g + h}= k + g - h \color{red}{-g + h}\)