geometry and area: find the area of a parallelogram if the two sides measure 24.1 inches and 31.4 inches and the shorter diagonal is 32.4 inches.
so the diagram looks like |dw:1429512718946:dw|
oops missed a side |dw:1429512759085:dw|
so have you done the law of cosines and area of a triangle using trig..?
yes
ok... so this is what I would do find the size of the angle x |dw:1429512883249:dw| using the law of cosines... to find x then use the area of a triangle \[A = \frac{1}{2} \times 24.1 \times 31.4 \times \sin(x)\] which gives the area of the lower triangle and double it to get the area of the parallelogram does that make sense..?
ok
but I don't have any angles to use the law of cosines its 3 sides right
yes, for an angle and if you made cos(x) the subject of the formula you would get \[\cos(x) = \frac{24.1^2 + 31.4^2 - 32.4^2}{2 \times 24.1\times 31.4}\]
ok I see
the right side of the equation gives a value less that 1... so \[x = \cos^{-1}(answer)\]
I did 1/2(24.1*31.4*70) = 26485.9
I think you forgot its sin(70) I think the angle is correct... \[Area = \frac{1}{2} \times 24.1 \times 31.4 \times \sin(70)\]
then double that area for the area of the parallelogram
355*2
yes... just be careful with rounding 2 early... Id say 711 inches^2
thank u so much
glad to help...
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