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OpenStudy (saylilbaby):
OpenStudy (saylilbaby):
i chose D
OpenStudy (saylilbaby):
@campbell_st
OpenStudy (saylilbaby):
@Nnesha
OpenStudy (campbell_st):
its not D
you need the discriminant\[\Delta = b^2 - 4ac\]
in the quadratic a = 6, b = -7 and c = -4
substitute them and calculate the value of the discriminant
the conditions are
\[\Delta = 0, ~ two~ real~ solutions, \]
\[\Delta = 0, ~ one ~repeated ~real ~solution\]
\[\Delta < 0,~ 2 ~imaginary~solutions\]
so calculate and check...
hope it helps
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OpenStudy (saylilbaby):
B @campbell_st
OpenStudy (campbell_st):
I don't think its B
\[\Delta = (-7)^2 - 4 \times 6 \times (-4)\]
OpenStudy (saylilbaby):
my answer was x=47 @campbell_st
OpenStudy (campbell_st):
well I think you need to check your calculation... do it the way I've written it...
but if you got 47... is that > 0? or < 0? or = 0?
OpenStudy (saylilbaby):
@rational @xo_kansasprincess_xo
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OpenStudy (saylilbaby):
@rational i pick B
OpenStudy (saylilbaby):
@dan815 @nightowl38 @Ashleyisakitty
OpenStudy (saylilbaby):
@wio @Kainui
OpenStudy (cp9454):
compare ur eqn with general form i.e. \[ax^2+bx+c=0\]. now find discriminat i.e. \[b^2-4ac\].
if D>0, sol. are real and distinct
if D=0, two equal real roots.
if D<0, two imaginry root.