help????Medal....fan
i chose D
@campbell_st
@Nnesha
its not D you need the discriminant\[\Delta = b^2 - 4ac\] in the quadratic a = 6, b = -7 and c = -4 substitute them and calculate the value of the discriminant the conditions are \[\Delta = 0, ~ two~ real~ solutions, \] \[\Delta = 0, ~ one ~repeated ~real ~solution\] \[\Delta < 0,~ 2 ~imaginary~solutions\] so calculate and check... hope it helps
B @campbell_st
I don't think its B \[\Delta = (-7)^2 - 4 \times 6 \times (-4)\]
my answer was x=47 @campbell_st
well I think you need to check your calculation... do it the way I've written it... but if you got 47... is that > 0? or < 0? or = 0?
@rational @xo_kansasprincess_xo
@rational i pick B
@dan815 @nightowl38 @Ashleyisakitty
@wio @Kainui
compare ur eqn with general form i.e. \[ax^2+bx+c=0\]. now find discriminat i.e. \[b^2-4ac\]. if D>0, sol. are real and distinct if D=0, two equal real roots. if D<0, two imaginry root.
here a=6, b=-7, c= -4. find D
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