Question

NEED HELP please: Cos (sin^-1(1/3) - tan^-1(1/2))

Find the exact value of the expression.

Answer 1

0.992345241211553801626983189764143358021255927794159535446727...

Answer 2

i need the answer in simplest fraction form, thanks tho

Answer 3

(4 sqrt(2/5))/3+1/(3 sqrt(5))

Answer 4

The textbook answer is (4sqrt10 + sqrt5)/15

But i need to see how you do it.

Answer 5

alternate form=1/15 (4 sqrt(10)+sqrt(5))

Answer 6

Can you explain to me how you got that?

Answer 7

cos(sin^(-1)(1/3)-tan^(-1)(1/2))
(result in radians)

Answer 8

cos(cot^(-1)(2)-csc^(-1)(3))

Answer 9

cos(sin^(-1)(1/3)-tan^(-1)(1/2)) = cosh(i (sin^(-1)(1/3)-tan^(-1)(1/2)))

Answer 10

cos(sin^(-1)(1/3)-tan^(-1)(1/2)) = cosh(-i (sin^(-1)(1/3)-tan^(-1)(1/2)))

Answer 11

cos(sin^(-1)(1/3)-tan^(-1)(1/2)) = 1/2 (e^(-i (sin^(-1)(1/3)-tan^(-1)(1/2)))+e^(i (sin^(-1)(1/3)-tan^(-1)(1/2))))

Answer 12

cos(tan^(-1)(1/2)-tan^(-1)(1/(2 sqrt(2))))

Answer 13

(4 sqrt(2/5))/3+1/(3 sqrt(5))

Answer 14

alternate form=1/15 (4 sqrt(10)+sqrt(5))

Answer 15

alright thank you very much

Answer 16

Do I look dumb?

Answer 17

What do you mean?

Answer 18

you dont trust me?

Answer 19

haha i had no doubt you had the answer right but i trying to review, so i wanted to see work to help me.

Answer 20

once again, thanks for your help wiz :)