What is the slope of the hypotenuses of the triangles in simplest form? First-quadrant graph showing a ray through the origin and the points (2, 4), (3, 6), and (5, 10). Two triangles have their longest sides with endpoints along the line, one vertical leg, and one horizontal leg. The first triangle has a longest side with endpoints at (2, 4) and (3, 6). The second triangle has a longest side with endpoints at (5, 10) and (3, 6). http://static.k12.com/calms_media/media/1503500_1504000/1503532/1/2f86043497482838775aa2b5f0bd5f65a773fbdd/MS_IMC-140523-130901.jpg
you just need to find the slope of the line
choose any two points on the line that you feel like, and plug them into the slope formula. The slope formula: \(\LARGE \color{black}{ \displaystyle {\rm m}=\frac{\color{blue}{{\rm y}_1}-\color{red}{{\rm y}_2}}{\color{green}{{\rm x}_1}-\color{darkgoldenrod}{{\rm x}_2}} }\) WHERE: \(\LARGE \color{black}{ \displaystyle {\rm m} }\) is the slope \(\Large\color{black}{ \displaystyle (\color{green}{{\rm x}_1}~,~~\color{blue}{{\rm y}_1}) }\) and \(\Large\color{black}{ \displaystyle (\color{darkgoldenrod}{{\rm x}_2}~,~~\color{red}{{\rm y}_2}) }\) are the points
as you have been shown in diagram change in y over change in x===4/2 or 2/1=2
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