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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (anonymous):
((x - 1)^2)/8^2 - ((y - 2)^2)/6^2 = 1
OpenStudy (anonymous):
(1, 2) and (11, 2)
(1, 2) and (1, 10)
(1, 12) and (1, –8)
(11, 2) and (–9, 2)
OpenStudy (anonymous):
OpenStudy (michele_laino):
referring to the standard equation of the hyperbola:
\[\frac{{{X^2}}}{{{a^2}}} - \frac{{{Y^2}}}{{{b^2}}} = 1\]
we get:
a=8, and b=6
Now the x-coordinate of the foci are :
\[c = \pm \sqrt {{a^2} + {b^2}} = ...?\]
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OpenStudy (michele_laino):
what are the values of c?
OpenStudy (anonymous):
I got a 10
OpenStudy (anonymous):
a ±10
OpenStudy (michele_laino):
ok!
so our foci are the points:
F1=(-c,0)=...?
and
F2=(c,0)=...?
OpenStudy (anonymous):
(-10,0) (10,0)?
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OpenStudy (michele_laino):
ok! that's right!
OpenStudy (anonymous):
so what else I do?
OpenStudy (michele_laino):
we have finished!
OpenStudy (anonymous):
none of the answers LOL
OpenStudy (michele_laino):
sorry you are right, since we have performed this traslation:
X=x-1
Y=y-2
so we have to solve this system:
x-1=10--->x=..?
and
x-1=-10---> x=...?
then we have to solve these equations:
y-2=0---< y=...?
y-2=0--->y=...?
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