Question

Please help !! A diver of mass 101 jumps upward off a diving board and into the water the diving board is 6m above the water

A when the diver jumps she has a speed of 1.2m/s how much kinetic energy does she have?

B how much gravational energy will she have gained at her highest point? Explain how you found your answer

C based on divers speed from part (a) how high above the board will she rise?

D how fast will the diver be moving when she hits the water?

Answer 1

so Kinetic energy is defined as .5*m*v^2 so when the diver jumps she has 1.2 m/s velocity her mass is 101 ... (kg? g?) but just plug those values in to get kinetic energy.

Gravitation energy is the same as potential energy which equals mgh where m is the mass g is gravity and h is height (6m ) so just plug in those values and yuo have that answer.

The velocity of a falling object in respect to displacement can be given by v = +/- (2*g*h +vi^2 ) you have all the components so you just need to solve that and youll have the speed of the fall.

Answer 2

if the assumptions embedded in answers to A) - C) are correct, she's gonna bang her head on the way down.

if this an applied maths exercise .....