Okay, so I have an idea of where to start here, but it's finding the sine values that are bothering me. The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used. C = 38°, a = 19, c = 10
what exactly about the sine values?
you are calculating side C?
oh nvm B
?
When solving the equation, they'd like me to look for all values of ABC, as well as side a.
I dont think a triangle can be formed
so what side are we trying to calculate though?
Solving for sin c got me a decimal, as it always does. The issue here is that sin ^-1 (answer) "should" calculate the decimal for me. I'm attempting to calculate angles C, A, and side a.
there is no triangle
For retrice(SSA) theorem sin(C) > c/a so there are no solutions and no triangle!
(retrice
\[(retrice\]
lol it wont let me put A S S
¯\_(ツ)_/¯
For A S S(SSA) theorem sin(c)>c/a so there are no solutions and no triangle
Yeah Niguyver is correct.
The way my lesson has instructed me to solve it, \[\sin b / b = \sin c /c \] which does give a decimal value, so I'm a little confused there.
there is no B
Wait, which one did I post... No, you're right. Crap. Got my questions mixed up.
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