Ask
your own question, for FREE!
Mathematics
7 Online
OpenStudy (anonymous):
Can Someone Help Please!!!! I GIVE MEDALS!!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Can someone explain i wanna know how to do it :/
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@XcrawfishX
OpenStudy (anonymous):
@love10129151
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@sleepyhead314
OpenStudy (sleepyhead314):
for this you can use the Pythagorean Theorem
a^2 + b^2 = c^2
in this case
c = 10
b = 4
and we want to find a
OpenStudy (anonymous):
okay so i would plug in 10 and 4 which would look like|dw:1429559164297:dw|
OpenStudy (sleepyhead314):
that is right :)
keep going :D
OpenStudy (anonymous):
Now how would i solve exactly?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
:) yay
OpenStudy (sleepyhead314):
a^2 + 4^2 = 10^2
becomes
a^2 + 16 = 100
a^2 = 84
a = square root of 84 = ?
OpenStudy (anonymous):
so i would reduce 84?
OpenStudy (sleepyhead314):
I would suggest plugging it into a calculator of some sort :)
OpenStudy (anonymous):
So i don't reduce?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (sleepyhead314):
you can
OpenStudy (anonymous):
oh let me reduce then brb
OpenStudy (anonymous):
it would be 9 cause 9 times 9 is 81 and 10 times 10 is 100, 100 is to big right?
OpenStudy (anonymous):
So it would be 9 right?
OpenStudy (sleepyhead314):
yeup ^_^
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
theres no nine .=.
OpenStudy (sleepyhead314):
the one closest to "9"? ;P
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!