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Mathematics 11 Online
OpenStudy (anonymous):

Please Check for me!!

OpenStudy (anonymous):

Mehek (mehek14):

that's correct

OpenStudy (anonymous):

Do you know this?

Mehek (mehek14):

use the pythagorean theorem

OpenStudy (anonymous):

nice pic @Mehek14

Mehek (mehek14):

does \(\large{16^2 + 32^2 = 36^2?}\)

OpenStudy (anonymous):

no

Mehek (mehek14):

i wasn't asking you

Mehek (mehek14):

@horsegirl325 does it?

OpenStudy (anonymous):

no @Mehek14

Mehek (mehek14):

now move to the second answer choice and check that one as well

OpenStudy (anonymous):

that ones not right

OpenStudy (anonymous):

not a nor b

geerky42 (geerky42):

Check B again.

geerky42 (geerky42):

\(5^2+12^2=?\)

Mehek (mehek14):

yea check B \(\large{5^2 + 12^2 = ?}\)

OpenStudy (anonymous):

Sorry, Its B.

Mehek (mehek14):

\(5^2 = 25\) \(12^2 = 144\) \(25 + 144 = 169\) \(\sqrt{169} = 13\)

OpenStudy (anonymous):

How would you solve this one @Mehek14

Mehek (mehek14):

Pythagorean Theorem \(4^2 + 7^2 = x^2\)

OpenStudy (anonymous):

ohh! I know give me a min to solve!!

Mehek (mehek14):

alright

OpenStudy (anonymous):

8?

OpenStudy (anonymous):

@Mehek14

Mehek (mehek14):

it would be 8.1

OpenStudy (anonymous):

Right! Thanks!

OpenStudy (anonymous):

Can you heck just 1 more?

Mehek (mehek14):

\(14^2 + x^2 = 20^2\)

Mehek (mehek14):

so find \(14^2 and~ 20^2\) and then subtract them

OpenStudy (anonymous):

14.3 @Mehek14

Mehek (mehek14):

correct \(\ddot \smile\)

OpenStudy (anonymous):

thank you

Mehek (mehek14):

yw

OpenStudy (anonymous):

Thank you!!!!

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