Question

Check my work! :)
Can \(2y^2 - 5y = -2\) become \(2y^2 - 5y + -2 = 0\)?

Answer 1

the change is incorrect, it should be
+2

Answer 2

Hello, Dan. :)

Answer 3

because you are going to add 2 to both sides to eliminate the -2 on the right

Answer 4

Right. Sorry, I forgot. Thank you for the correction.

Answer 5

Okay, now get to factoring

Answer 6

I am learning the Quadratic Formula and I had to get my equation to look like this: \[-b \pm \sqrt{b^2 - 4ac} \over 2a\]

Answer 7

\[2y^2-5y+2=0\\\]
a=2, -5=b, 2=c

Answer 8

you see the coefficients, a is the coefficient on the y^2(other wise known as the 2nd degree term), b is the coefficient on the y term( of the 1st degree term) and c is the constant ( or the 0th degree term)

Answer 9

Yes, I see. :)