Check my work! :)
Can $2y^2 - 5y = -2$ become $2y^2 - 5y + -2 = 0$?

Question

dan815 · Answer

the change is incorrect, it should be 
+2

anonymous · Answer

Hello, Dan. :)

dan815 · Answer

because you are going to add 2 to both sides to eliminate the -2 on the right

anonymous · Answer

Right. Sorry, I forgot. Thank you for the correction.

dan815 · Answer

Okay, now get to factoring

anonymous · Answer

I am learning the Quadratic Formula and I had to get my equation to look like this: $$-b \pm \sqrt{b^2 - 4ac} \over 2a$$

dan815 · Answer

$$2y^2-5y+2=0\$$
a=2, -5=b, 2=c

dan815 · Answer

you see the coefficients, a is the coefficient on the y^2(other wise known as the 2nd degree term), b is the coefficient on the y term( of the 1st degree term) and c is the constant ( or the 0th degree term)

anonymous · Answer

Yes, I see. :)