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When 1.045 g of CaO is added to 50 mL of water at 25 degrees Celsius in a caloriemeter, the temp of the water increases to 32.3 degrees Celsius. Assuming the specific heat of the solution is 4.18 J/K*C and that the calorimeter itself absorbs a negligible amount of heat, calculate delta H (enthalpy in kilojoules) for the reaction CaO(s) + H20(l) ---> Ca(OH)2(aq)
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You can solve this using the following equation: \[\Delta Hn=-mc \Delta T\]
What would be the value of m and c
The m is referring to the mass of the water in the calorimeter. The c is the specific heat of water.
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