Question

A hyperbola is given by x2 − 4xy + y2 + 2 = 0. What is its equation in standard form if the axes are rotated so that the axes of the hyperbola lie on the rotated coordinate axes?

Answer 1

\[(x' ^2)/(((3\sqrt(2))/2)) - (y' ^2)/(((3\sqrt(2))/2)) = 1 \]

Answer 2

\[(x' ^ 2)/2 - (y' ^ 2)/((2/3)) = 1 \]

Answer 3

\[(x' ^ 2)/((1/2)) - (y' ^ 2)/((1/2)) = 1 \]

Answer 4

\[(x' ^ 2)/4 - (y' ^ 2)/4 = 1 \]

Answer 5

@undeadknight26

Answer 6

Holy ****.

Answer 7

lol

Answer 8

I will show you how it is set up

Answer 9

I am guessing you posted this on answers.com too eh? xD

Answer 10

you already know

Answer 11

Hahah ;)
Power of google.

Answer 12

:/

Answer 13

I trying to show how it is set up but...

Answer 14

Waz wrong?

Answer 15

@nincompoop @skullpatrol ;-;

Answer 16

\[\frac{ x^2 }{ (\frac{ 3\sqrt{2} }{ 2}}-\]

Answer 17

ok thats the first half of A

Answer 18

\[\frac{ y^2 }{ (\frac{ 3 \sqrt{2}}{ 2 }) }=\]

Answer 19

got it

Answer 20

\[\frac{ x^2 }{ (\frac{ 3\sqrt{2} }{ 2})}- \frac{ y^2 }{ (\frac{ 3 \sqrt{2}}{ 2 }) }= 1\]

Answer 21

And thats A

Answer 22

but nobody knows what im doing so....

Answer 23

You are too advanced ;-;
I am just a 10th grade simpleton ;-;

Answer 24

ok

Answer 25

@jigglypuff314

Answer 26

@satellite73