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Mathematics 8 Online
OpenStudy (anonymous):

FAN AND MEDAL

OpenStudy (anonymous):

you will need two coins. First, you will determine the theoretical probability of events. Then, you will flip the coins 100 times and determine the experimental probability of the events. Flip two coins 100 times, and record the results of each coin toss in a table like the one below:

OpenStudy (anonymous):

Result Frequency Two heads lllll lllll lllll lllll lllll ll Two tails lllll lllll lllll lllll lllll l One head, one tail lllll lllll lllll lllll lllll lllll lllll lllll lllll ll

OpenStudy (anonymous):

1. What is the theoretical probability that a coin toss results in two heads showing?

OpenStudy (anonymous):

3. What is the theoretical probability that a coin toss results in two tails showing?

OpenStudy (anonymous):

5. What is the theoretical probability that a coin toss results in one head and one tail showing?

OpenStudy (phi):

what is the probability of getting heads for 1 toss of a coin ?

OpenStudy (anonymous):

50%

OpenStudy (phi):

now flip it again. it's 1/2 or 0.5 chance of getting a second head if the events are independent (which means the first flip does not affect the second flip), you multiply the two probabilities. 1/2 * 1/2 = ?

OpenStudy (anonymous):

100%

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

2/2

OpenStudy (phi):

are you saying you can't multiply \[ \frac{1}{2} \cdot \frac{1}{2} \] ?

OpenStudy (phi):

to mult fractions, top*top divided by bottom * bottom

OpenStudy (phi):

or if you write 1/2 as a decimal 0.5 0.5 * 0.5

OpenStudy (anonymous):

so it is 0.25

OpenStudy (phi):

yes, the theoretical chance of getting 2 heads is 1/4 or 0.25 by the same reasoning that is also the theoretical prob of getting 2 tails

OpenStudy (anonymous):

okay so it's 2/4 or 0.50 chance for getting head and tails right?

OpenStudy (phi):

yes. there are a few ways to figure it: if 0.25 for two heads and 0.25 for two tails and xx for h /t and it has to add up to 1 (or 100%) we have 0.25+0.25+x = 1 0.5 + x = 1 x= 1-0.5 x=0.5 i.e. 1/2 chance of getting a head and a tail (in any order)

OpenStudy (phi):

the other way is to say 1/2 chance of getting a T. then on the 2nd flip 1/2 chance of getting H so 1/2 *1/2 = 1/4 chance for getting TH also 1/2 chance of first getting H, then 1/2 for T and 1/4 chance for getting HT so the chance of TH or HT is 1/4+1/4 = 1/2

OpenStudy (anonymous):

thanks so much

OpenStudy (phi):

your "flip experiment" should get something close to 25 heads 25 tails 50 head/tail

OpenStudy (anonymous):

i got the answer for that i got 27, 26 and 47

OpenStudy (phi):

yes, those numbers are close to the theoretical, and are reasonable.

OpenStudy (anonymous):

thanks so much for your help :)

OpenStudy (phi):

yw

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