Question

Help Plz

Answer 1

@conner143

Answer 2

hey can you help me with like 15 questions plz?

Answer 3

the first one is \[\sqrt{85}\] again

Answer 4

\[\sqrt{162}\] is the second one

Answer 5

@Michele_Laino

Answer 6

we have to compute the base and the height of your rectangle

Answer 7

I have a lot of questions...so you can just give me the answers

Answer 8

I'm sorry, I can not give you the answer directly, since I have to respect the Code of Conduct

Answer 9

ok, how do we compute the height and the base of the rectangle?

Answer 10

the base of your triangle is given by the distance between points (-1,-3) and (1,3)
such distance is:
\[\begin{gathered}
d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \sqrt {{{\left( { - 1 - 1} \right)}^2} + {{\left( { - 3 - 3} \right)}^2}} = \hfill \\
= \sqrt {4 + 36} = ...? \hfill \\
\end{gathered} \]

Answer 11

whereas the height, is given by the distance between the points (1,3) and (-2,4)
\[\begin{gathered}
d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \sqrt {{{\left( { - 2 - 1} \right)}^2} + {{\left( {4 - 3} \right)}^2}} = \hfill \\
= \sqrt {9 + 1} = ...? \hfill \\
\end{gathered} \]

Answer 12

40, 10?

Answer 13

base=sqrt(40)
height=sqrt(10)
so:
area is:
\[area = \sqrt {40} \times \sqrt {10} = \sqrt {400} = ...?\]

Answer 14

20

Answer 15

that's right!

Answer 16

here the area of your polygon, is equal to area of the rectangle TSPG plus area of triangle PSE

Answer 17

now area of rectangle TSPG = 7*5=...?

Answer 18

35

Answer 19

ok! and area of triangle PSE= (7*2)/2=...?

Answer 20

7

Answer 21

ok! so the requested area = 35+7=...?

Answer 22

42

Answer 23

that's right!

Answer 24

here we have to break your polygon into one parallelogram, and 3 triangles, like below:

Answer 25

area of parallelogram = 6*3=...?

Answer 26

18

Answer 27

ok!
area of triangle 2=(3*1)/2=...?

Answer 28

1.5

Answer 29

ok!
area of triangle 3= (4*3)/2=...?

Answer 30

6

Answer 31

ok!
area of triangle 4 = (6*3)/2=...?

Answer 32

9

Answer 33

ok!
so the area of your polygon is:
area = 18+1.5+6+9=...?

Answer 34

34.5

Answer 35

that's right!

Answer 36

here, we to compute the base and the height of your rectangle.
Now the base of your rectangle is given by the distance between the points (1,2) and (5,0), so we have:
\[\begin{gathered}
base = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \sqrt {{{\left( {5 - 1} \right)}^2} + {{\left( {0 - 2} \right)}^2}} = \hfill \\
= \sqrt {16 + 4} = ...? \hfill \\
\end{gathered} \]

Answer 37

20=4.47

Answer 38

whereas the height is given by the distance between points (1,2) and (2,4), namely:
\[\begin{gathered}
height = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \sqrt {{{\left( {2 - 1} \right)}^2} + {{\left( {4 - 2} \right)}^2}} = \hfill \\
= \sqrt {1 + 4} = ...? \hfill \\
\end{gathered} \]

Answer 39

better is base = sqrt(20)

Answer 40

square root of 5

Answer 41

ok! so area is:
\[area = \sqrt {20} \times \sqrt 5 = \sqrt {100} = ...?\]

Answer 42

10

Answer 43

ok! so we have:
number of acres = 9*10=...?

Answer 44

90

Answer 45

ok! so the price per acre is:
423000/90=...?

Answer 46

4,700

Answer 47

that's right!

Answer 48

here is your triangle: