Need help asap
If 23.14g calcium phosphate, 12.20g silicon dioxide, and necessary amount of carbon react, 2Ca *little 3* (PO *little 4*) *Little 2* + 6SiO *little 2* + 10C - P *little 4* + 6CaSiO *Little 3* + 10 CO, How many grams of CaSiO *little 3* are produced?

Question

Need help asap
If 23.14g calcium phosphate, 12.20g silicon dioxide, and necessary amount of carbon react, 2Ca *little 3* (PO *little 4*) *Little 2* + 6SiO *little 2* + 10C -> P *little 4* + 6CaSiO *Little 3* + 10 CO, How many grams of CaSiO *little 3* are produced?

jfraser · Answer

you need to turn all those masses into $moles$, and compare them to make sure the amounts you have will all be used up.

This may be a limiting reactant problem, the moles of each reactant will tell you if it is

anonymous · Answer

I don't understand how to do that though. I'm stuck in ISS and my chemistry teacher taught it to me a long time ago. I don't know how to do that.

jfraser · Answer

Do you know how to find the molar mass of calcium phosphate $Ca_3(PO_4)_2$?

anonymous · Answer

no

jfraser · Answer

grab a periodic table and find the masses of Ca, P, and O

jfraser · Answer

they will be listed on the key of whatever table you have

anonymous · Answer

okay. Ca is 40.08...P is 30.974...O is 15.999

jfraser · Answer

good, so calcium phosphate has 3 Ca's, 2 P's, and 8 O's. Add up all those masses and find the total

jfraser · Answer

that's what $one$ mole of calcium phosphate should weigh. You've got a whole lot less than that, so you'll have just a $fraction$ of a mole of $Ca_3(PO_4)_2$

anonymous · Answer

so 23.14 grams?

jfraser · Answer

you've got 23.14g, which is a whole lot less than what one mole weighs, am I right?

anonymous · Answer

yes

jfraser · Answer

how many moles of calcium phosphate do you start with?

jfraser · Answer

(take the 23.14g and divide by the molar mass, 310g/mol)

anonymous · Answer

hi

anonymous · Answer

you starts off with 2 moles of calcium phosphate right?

jfraser · Answer

no, you start with 23.14g of calcium phosphate, which is a whole lot less than what 2 moles weighs

jfraser · Answer

the balanced reaction tells you the $relative amounts$ of each reactant that get used, but the masses you start with tell you how much actually gets used

anonymous · Answer

yes

anonymous · Answer

so confused!!!!!!

anonymous · Answer

why  are you confused ???????

anonymous · Answer

It doesn't make sense to me...

anonymous · Answer

what doesn't make sense  to you  i get it

anonymous · Answer

I don't understand where he is applying any of this stuff