What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 10.0% NaOH by mass?

Question

aaronq · Answer

10 % by mass means that there is 10 g of NaOH for every 100 g of solution (i.e. 10 g NaOH and 90 g of $H_2O$)

anonymous · Answer

Do you get it, @sk8fux?

anonymous · Answer

I'm a little rusty on how to find the mole fraction and molality from that still

anonymous · Answer

Well, as you may know, $X= \large \frac{moles~of~NaOH }{moles~of NaOH+moles~of ~H_2O}$. Find moles of each species and you will find $X$ easily

anonymous · Answer

$Molality= \large \frac{moles~ of~ solute}{kg~of~solvent}$. In this problem, NaOH is solute while $\sf {H_2O}$ is solvent. Just remember to change from $\sf g$ to $\sf kg$. That's it

anonymous · Answer

I always get stuck on the easy ones....thanks so much!

anonymous · Answer

You are very welcome