Question

Look below for picture (fan and medal!!!)

Answer 1

\(\bf H=-\cfrac{1}{2}gt^2+vt+h\quad
\begin{cases}
g=32\\
v=62\\
h=\textit{starting point from the ground}\\
\textit{it began from ground level, thus}=0
\end{cases}\\ \quad \\ H=-\cfrac{1}{2}32t^2+62t+0
\\ \quad \\
H=-16t^2+62t\implies {\color{brown}{ 0}}=-16t^2+62t\)

solve for "t"