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Methane gas, CH4, is sold in a 43.8L cylinder containing 5.54kg of CH4. what is the pressure in the cylinder in kilopascal at 20C?
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First, what was the original temperature or can I assume that the first temperature is in standard temperature 0 degree celsius or 273 degrees Kelvin?
They didn't give the original temperature
Alright then, I will use the combined gas law. I will write the formula down and post it in a few moments.
correction ideal gas law
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why are we using 8.31 for R instead of .082?
The reason why we are using 8.31 is because it is already written in kPa.
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