Question

help ; ;
Find the vertex, focus, directrix, and focal width of the parabola. -1/40x^2=y

Answer 1

@geerky42 i cant find the focal width

Answer 2

HI!!

Answer 3

hello xD

Answer 4

Not very familiar with it, sorry.

Answer 5

i know the vertex is 0.0

Answer 6

focal width of \(4py=x^2\) is \(|4p|\) that is all, you don't really find it, it is right there

Answer 7

um not in my answer choices, ive narrowed it down to two

Answer 8

either 40 or 160

Answer 9

\[-\frac{1}{40}x^2=y\\
-40y=x^2\] is a nice way to write the parabola, you get the vertex directrix, focus, and focal width by looking

Answer 10

it is \(40\) not \(4\times 40\)

Answer 11

so its 160 xD

Answer 12

NO!!

Answer 13

just \(40\)

Answer 14

oh i miss interpreted you answer xD

Answer 15

i got 4x40 lol

Answer 16

you get the vertex as \((0,0)\) right?

Answer 17

yup

Answer 18

how about the rest ?

Answer 19

and focus as 0,-10

Answer 20

and the directrix of y as 10

Answer 21

yup

Answer 22

yup

Answer 23

i might need your help again so be attentive xD

Answer 24

look like you got it all