Question

Gloria had 2 sets of alphabet cards (A-Z). She mixed the two sets together to form a single stack of cards. Then Gloria drew three cards from the stack without replacing them. What is the probability that she drew either a card with an L or a card with an R all three times?

Answer 1

use the complement

Answer 2

There are 52 cards in the stack initially, of which 4 cards are either an L or an R.
The probability that she drew either a card with an L or a card with an R all three times is given by:
\[\large P(3\ of\ L\ or\ R)=\frac{4C3}{52C3}=you\ can\ calculate\]

Answer 3

not really... no I can't that looks like elvish

Answer 4

4C3 means the number of combinations of four things taken three at a time.
52C3 means the number of combinations of fifty two things taken three at a time.
Are you familiar with combinations?

Answer 5

no... im in 7th grade

Answer 6

Then another method is as follows:
The probability of drawing an L or an R on the first draw is 4/52.
Having drawn an L or an R on the first draw, the probability of drawing an L or an R on the second draw is 3/51.
Having drawn an an L or an R on the first and the second draws, the probability of drawing an L or an R on the third draw is 2/50.
Therefore the required probability is given by:
\[\large P(3\ of\ L\ or\ R)=\frac{4\times3\times2}{52\times51\times50}=you\ can\ calculate\]

Answer 7

so, it's 24 over 132600 which reduces to 1 over 5525?

Answer 8

which is more of a possibility than winning the lottery.

Answer 9

You are correct in your answer (and your observation)!