Question

fan and medal

Answer 1

Find an equation for the nth term of the sequence. (1 point)

-3, -12, -48, -192, ...

an = 4 -3n + 1
an = -3 4n - 1
an = -3 4n
an = 4 -3n
6. Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively. (1 point)

an = 7 (-3)n + 1
an = 7 3n - 1
an = 7 (-3)n - 1
an = 7 3n

Answer 2

nth?

Answer 3

oh this is easy

Answer 4

-3 is the first term in the sequence

Answer 5

a1=-3

Answer 6

an = a1 + (n - 1)d

Answer 7

n= 4

Answer 8

nah the first term for the second one is 7

Answer 9

so an = -3 4n - 1??

Answer 10

@Niguyver

Answer 11

It could be C

Answer 12

\[T_{n} = ar^{n -1} \]

Answer 13

that is the equation for geometric

Answer 14

so you have for the 2nd term

−21=ar

Answer 15

and the 5th term

567=ar^4

Answer 16

wait, this is for 1st question write?

Answer 17

no 2nd one

Answer 18

this can be written as

567=ar×r^3

Answer 19

substitute the information from the 2nd term

567=−21×r3

Answer 20

an = 7 3n?

Answer 21

I got c could be wrong though

Answer 22

an = 7 (-3)n - 1 ?

Answer 23

this is wrong?

Answer 24

Yea I did get C but I could be wrong

Answer 25

okay, that's fine :)
Thank you so much

Answer 26

@Niguyver

Answer 27

yea np