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Find the lcoal min and max values of the function. f(x)= 2x^3+15x^2-36x
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I got this so far: f '(x)= 6x^2+30x-36, then I set it to zero x=2,3
+10x for the middle term, ya?
oops I mean 15x^2, sorry about that!
\[\Large\rm 0=6x^2+30x-36\]Divide a 6 out of everything,\[\Large\rm0=x^2+5x-6\]Hmm your solutions look a little off. I think it factors differently.
Not 2 and 3, try the other factors of 6 :D
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oops! It's x= -6 and 1
Ya there we go!
Thanks @zepdrix ! I got it from here. Stupid me on factoring the equation wrong :/
cool c:
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