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Mathematics 8 Online
OpenStudy (anonymous):

Hi everyone. Can someone help me check this inverse Laplace transform?

OpenStudy (anonymous):

\[e^-3s/s^2\]

OpenStudy (anonymous):

\[(e ^{-3s})/(s^2)\]

OpenStudy (anonymous):

So I though the -3 would indicate t+3 in time domain and the inverse laplace of 1/s^2 is the unit ramp function r(t) or tu(t)

OpenStudy (anonymous):

so r(t+3)......my solution says r(t-3)

OpenStudy (anonymous):

uc(t)f(t-c), c = 3 f(t) = t^n ... uc(t) (t-3)^n

OpenStudy (anonymous):

http://tutorial.math.lamar.edu/pdf/Laplace_Table.pdf line 27, 3

OpenStudy (anonymous):

n =1

OpenStudy (anonymous):

Awesome thank you!

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