Question

Assuming 100% dissociation, calculate the freezing point and boiling point of 1.47 m Na2SO4(aq).

Freezing point for H2O is 1.86, Boiling Point is .512

Answer 1

You can find both using the following equations:

\[\Delta T_b=iK_bm\]\[\Delta T_f=iK_fm\]
Where the ΔT's are the changes in boiling/freezing point, i is the van't Hoff factor, the K's are the boiling point/freezing point constants (given at the end of your question), and m is the molality.

Plugging the appropriate values into these equations will give you the changes in the freezing and boiling points and therefore your answers!

Answer 2

So simple, thank you so much.