Question

Find a point on the y-axis that is equidistant from (5,-5) an (1,1)

Answer 1

let the point (0, y) is equidistant from the given points

(5 - 0)^2 + (-5 - y)^2 = (1 - 0)^2 + (1 - y)^2

=> 25 + 25 + y^2 + 10y = 1 + 1 + y^2 - 2y

=> 50 + 10y = 2 - 2y

=> 12y = -48

y = -4

The required point is (0, -4)

Answer 2

@Athenalexis do you get it?

Answer 3

@Hannah_Waller yes I have one more question could you help me ?

Answer 4

i can try @Athenalexis

Answer 5

@Hannah_Waller Show that the points A(-2, 6), B(5, 3), C(-1, -11) and D(-8, -8) are the vertices of a rectangle.

Answer 6

IM not real sure how to do this one i looked it up andthis seems to mabye be something like what you are looking for, http://www.homeworklib.com/question_13834_a-rectangle-is-defined-by-the-vertices-a65-b121-c813-and-d107#.VTeyX5PCefg hope it helps

Answer 7

@Athenalexis

Answer 8

thank you so much @Hannah_Waller