Two metal balls have charges of 7.1 * 10ÈÒ coulombs and
6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls?
(k = 9.0 * 10© newton·metersÆ/coulombÆ)

Question

Two metal balls have charges of 7.1 * 10ÈÒ coulombs and
6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls?
(k = 9.0 * 10© newton·metersÆ/coulombÆ)

anonymous · Answer

@ghuczek can you help me?

anonymous · Answer

Hey, start off by drawing a diagram.

anonymous · Answer

thanks batman how do i do that though

anonymous · Answer

the answer choices are 
a. 5.7 newtons
b. 6.9 newtons
c. 7.1 newtons
d. 1.4 newtons

anonymous · Answer

|dw:1429715020740:dw| should look as such, you have to use the formula $$F_e = \frac{ k|q_1| |q_2| }{ r^2 }$$ which is Coulombs law.

anonymous · Answer

I'm not sure if you put the right numbers, so I put question marks.

anonymous · Answer

i did, how do you find the answer?

anonymous · Answer

You should notice I put absolute value on the charges, you just plug the numbers in that formula.

anonymous · Answer

Your charges are q1 and q2 as I listed

anonymous · Answer

k is couloumbs constant which is $$k = 8.99 \times 10^9 N m^2/C^2$$

anonymous · Answer

d in this case is your r, so d = r :) That should be enough information for you to do it!

anonymous · Answer

so do i just use the calculator now?

anonymous · Answer

Yeah, by the way it's crucial you understand this problem because it will just get harder from there, as in you will have multiple charges at different angles and such :P, so try to understand the formula as well.

anonymous · Answer

yeah im just trying to graduate so i dont really want to further my knowledge in physics

anonymous · Answer

Physics is wonderful friend! It's all around you! I hope you will change your mind, but as for this problem goes I hope you got it!