A boy drops a 2.50 kg rock down a 250 m well and listens for the echo. The air temperature is 0°C. How long after the stone is dropped will the boy hear the echo? The speed of sound through air at 0°C is v = 331 m/s. ***Not sure how to solve this? Thank you!! :)
the requested time is the time needed to the rock for reaching the bottom of the well plus the time needed to sound to reach the boy.
oh!
now the time needed to the rock to reaching the bottom of the well is given by the subsequent formula: \[\Large t = \sqrt {\frac{{2h}}{g}} \] where g is the gravity, namely g=9.81 m/sec^2, and h=250 meters. So what is: \[\Large t = \sqrt {\frac{{2h}}{g}} = \sqrt {\frac{{2 \times 250}}{{9.81}}} = ...?\]
okay, so then we get 7.142857143? is that the final answer? :/ it takes about 7 seconds?
the time needed to sound for reaching the boy is: t=250/331=0.755 seconds, so the requested time, is: 7.14+0.755=7.895 seconds
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