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Mathematics 8 Online
OpenStudy (anonymous):

Two cars raced at a race track. The faster car traveled 20 mph faster than the slower car. In the time that the slower car traveled 165 miles, the faster car traveled 225 miles. If the speeds of the cars remained constant, how fast did the slower car travel during the race?

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

looks like a distance equals rate times time problem we need a variable

OpenStudy (misty1212):

lets call the speed of the slower car \(x\) so the faster one will have speed \(x+20\)

OpenStudy (misty1212):

since time is distance divided by rate, you have \[T=\frac{165}{x}=\frac{225}{x+20}\] they are equal because the time is the same solve that equation for \(x\)

OpenStudy (misty1212):

start with \[165(x+20)=225x\]and solve that for \(x\)

OpenStudy (anonymous):

distance is always positive.

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