Question

IM STUCK HELP!!!


Suppose you divide a polynomial by a binomial. How do you know if the binomial is a factor of the polynomial? Create a sample problem that has a binomial which IS a factor of the polynomial being divided, and another problem that has a binomial which is NOT a factor of the polynomial being divided.

Can someone show me an example?

Answer 1

@mathsciencehistory

Answer 2

The remainder is zero.

Answer 3

@robtobey what?

Answer 4

binomial is a function of ax^2+bx+c? then i can help, cuz am not used to the englisch names.

Answer 5

if thats the case its like this, it prob looks like a divition u made when u were about 10 years old but its kinda diffrent:
6x^3+2x^2+24x+8 divided by x^2+4

Answer 6

write like this:
6 2 24 8 / x^2+0x+4
-6 0 -24 /6x
=0 2 0 8/6x+2
0 -2 0 -8
= 0 0 0 0 so our therm in x^3 can be divided by our therm in x^2

Answer 7

thanks

Answer 8

was that wat our asking?

Answer 9

yes thank you

Answer 10

+ i made it abit shroter for typing but the principe is:
u write the coefficients of our therm like
6 (x^3) 2(x^2) 24(x) 8 divided (/) x^2+0x+4
now u c what coeff u need to multiply x^2 to get 6x^3 aswer 6x
write 6x beneath x^2+0x
and use the multiplaction 6x*(x^2+4)= 24x^3 + 24x therefore the -6 and -24 beneath the 6 and 24. after this u need to substract, and thats why i already multiplied it by -1.

Answer 11

note that its not necesarry u get the same numbers when u do this, but at the end there will be 0 0 0 0 if they can be divided by each otehr.