If y is 6 when x is 3 and y varies directly with x, find y when x is 8. 4 11 16
Hey Katelyn :) If y varies `directly` with x`, we can show this relationship as,\[\Large\rm y=kx\] This problems requires us to find some constant of variation, \(\Large\rm k\), first.
We'll use the first set of information they gave us to figure out k. When y=6, x=3, \[\Large\rm 6=k\cdot3\]
What do you get for your k value? :)
3?
im not sure
Hmm so the 3 is `multiplying` the k. To solve for k, we'll do the opposite. We'll divide both sides by 3.
which is 2
\[\Large\rm \frac{6}{3}=k\]Ok good :)
We go back to our original equation, and plug the k in.\[\Large\rm y=kx\]\[\Large\rm y=2x\]
When x=8, what is your y?\[\Large\rm y=2\cdot8\]
16
Yayyy good job \c:/
yay!:) thank you!!
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