If y is 6 when x is 3 and y varies directly with x, find y when x is 8.
4
11
16
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OpenStudy (anonymous):
Hey Katelyn :)
If y varies `directly` with x`, we can show this relationship as,\[\Large\rm y=kx\]
This problems requires us to find some constant of variation, \(\Large\rm k\), first.
OpenStudy (anonymous):
We'll use the first set of information they gave us to figure out k.
When y=6, x=3,
\[\Large\rm 6=k\cdot3\]
OpenStudy (anonymous):
What do you get for your k value? :)
OpenStudy (anonymous):
3?
OpenStudy (anonymous):
im not sure
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OpenStudy (anonymous):
Hmm so the 3 is `multiplying` the k.
To solve for k, we'll do the opposite.
We'll divide both sides by 3.
OpenStudy (anonymous):
which is 2
OpenStudy (anonymous):
\[\Large\rm \frac{6}{3}=k\]Ok good :)
OpenStudy (anonymous):
We go back to our original equation, and plug the k in.\[\Large\rm y=kx\]\[\Large\rm y=2x\]
OpenStudy (anonymous):
When x=8, what is your y?\[\Large\rm y=2\cdot8\]
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