Question

Can someone help me here?

Answer 1

@Michele_Laino

Answer 2

hint:
if we substitute the value of z=6 into the first and the third equation, we get:
\[\left\{ \begin{gathered}
- x + 2y + 6 = 10 \hfill \\
3x - 2y + 12 = 8 \hfill \\
\end{gathered} \right.\]
now you can solve that system using, for example, the substitution method

Answer 3

where does 6 go at

Answer 4

the x or y

Answer 5

z is 6

Answer 6

we can rewrite that system as below:
\[\left\{ \begin{gathered}
- x + 2y = 4 \hfill \\
3x - 2y = - 4 \hfill \\
\end{gathered} \right.\]

Answer 7

Now if I add both equations each other, I get:
2x=0
so x=0
is it ok?

Answer 8

yes ok

Answer 9

now I substitute x=0, into the first equation, so I get:
2y=4,
what is y?

Answer 10

2

Answer 11

that's right!
so the solution of your system is:x=0, y=2, and z=6
namely the first option

Answer 12

awesome