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Mathematics 18 Online
OpenStudy (anonymous):

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent. P(red and yellow) ≈ ________ %

OpenStudy (anonymous):

@TheSmartOne @abb0t @HaileyD @amistre64 @Hero @EclipsedStar @freckles @jim_thompson5910 @JackofallTradez @kidrah69 @KyanTheDoodle @Nnesha

OpenStudy (anonymous):

Follow these steps: A) Number of red marbles = ? B) Total number of marbles before first drawing = ? C) Divide number in A) by number in B) D) Number of yellow marbles = ? E) Total number of marbles left after first drawing = ? F) Divide number in D) by number in E) G) Multiply number in C) by number in F) H) Your solution is the product in G)

OpenStudy (anonymous):

i am not sure, i need help, i will give medla and fan

OpenStudy (anonymous):

When you do , The correct answer is red = 14 marbles = 56%, then yellow = 12 marbles = 46%

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

step e is confusing

jimthompson5910 (jim_thompson5910):

let's go through it step by step we have 14 red marbles. How many marbles are there total?

OpenStudy (anonymous):

26

OpenStudy (anonymous):

for step c i got 1.85 (and a whole bunch of other random numbers)

OpenStudy (anonymous):

and for step d i got 12

jimthompson5910 (jim_thompson5910):

so the probability of drawing red is 14/26 I divided the number of red by the number total

OpenStudy (anonymous):

i got 7/13

jimthompson5910 (jim_thompson5910):

after you draw a red marble, how many total marbles are left?

OpenStudy (anonymous):

if u draw 1, that would be 25

jimthompson5910 (jim_thompson5910):

so what is the probability of getting yellow?

OpenStudy (anonymous):

is it 25?

jimthompson5910 (jim_thompson5910):

you represent it as a fraction (see how I did red above)

OpenStudy (anonymous):

25/26

jimthompson5910 (jim_thompson5910):

how many yellow?

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

there is 12 yellow

OpenStudy (anonymous):

i simplified 25/26 and got 0.961538

OpenStudy (anonymous):

that is in decimal

OpenStudy (anonymous):

in percent it is...

jimthompson5910 (jim_thompson5910):

so the probability of picking yellow is 12/25

jimthompson5910 (jim_thompson5910):

first draw: probability of picking red = 14/26 second draw: probability of picking yellow = 12/25

jimthompson5910 (jim_thompson5910):

multiply them together (14/26)*(12/25) = 0.25846153846153

OpenStudy (anonymous):

okay... i am following u

jimthompson5910 (jim_thompson5910):

then just convert 0.25846153846153 to a percent and you're done

OpenStudy (anonymous):

25.846153846%

OpenStudy (anonymous):

that is what I got @jim_thompson5910

OpenStudy (anonymous):

am i right?

OpenStudy (anonymous):

which is rounded to 26

jimthompson5910 (jim_thompson5910):

yeah 26% looks good

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