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OpenStudy (anonymous):
@misty1212 @acxbox22
OpenStudy (anonymous):
3 - 4 - 5 is a favorite
OpenStudy (anonymous):
|dw:1429751798086:dw|
OpenStudy (anonymous):
I think its B.
OpenStudy (anonymous):
\[5^2+b^2=12^2\\
25+b^2-144\\
b^2=144-25\\
b^2=119\] one more step and you are done
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OpenStudy (anonymous):
seems unlikely that \(\sqrt{119}=7\) doesn't it?
OpenStudy (anonymous):
i think so to
OpenStudy (anonymous):
D!!!
OpenStudy (here_to_help15):
A^2+B^2=C^2
OpenStudy (anonymous):
yes d!!!!!!
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OpenStudy (here_to_help15):
C^2 would be your hypotenuse
OpenStudy (here_to_help15):
the rest would be ur adjacent or sides
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Yep!!
OpenStudy (here_to_help15):
so plug in ur numbers
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OpenStudy (anonymous):
what about this one?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
bye
OpenStudy (here_to_help15):
5^2+B^2=12^2
V V
25 144
If you had just sides you would add but since its a side and hypotenuse in the mix you will subtract. Hypotenuse is the longest side. So in this case we are subtracting.
144-25=119
Now you will square whatever you got from what you subtracted.
\[\sqrt{119}\]
you would get 10.90 try having a calculator handy to make it easier to square for you :)