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Mathematics 21 Online
OpenStudy (anonymous):

Pythagorean theorem help!!!

OpenStudy (anonymous):

@misty1212 @acxbox22

OpenStudy (anonymous):

3 - 4 - 5 is a favorite

OpenStudy (anonymous):

|dw:1429751798086:dw|

OpenStudy (anonymous):

I think its B.

OpenStudy (anonymous):

\[5^2+b^2=12^2\\ 25+b^2-144\\ b^2=144-25\\ b^2=119\] one more step and you are done

OpenStudy (anonymous):

seems unlikely that \(\sqrt{119}=7\) doesn't it?

OpenStudy (anonymous):

i think so to

OpenStudy (anonymous):

D!!!

OpenStudy (here_to_help15):

A^2+B^2=C^2

OpenStudy (anonymous):

yes d!!!!!!

OpenStudy (here_to_help15):

C^2 would be your hypotenuse

OpenStudy (here_to_help15):

the rest would be ur adjacent or sides

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Yep!!

OpenStudy (here_to_help15):

so plug in ur numbers

OpenStudy (anonymous):

what about this one?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

bye

OpenStudy (here_to_help15):

5^2+B^2=12^2 V V 25 144 If you had just sides you would add but since its a side and hypotenuse in the mix you will subtract. Hypotenuse is the longest side. So in this case we are subtracting. 144-25=119 Now you will square whatever you got from what you subtracted. \[\sqrt{119}\] you would get 10.90 try having a calculator handy to make it easier to square for you :)

OpenStudy (here_to_help15):

@satellite73 my favorite as well :)

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