Question

6- 2^x +log 5=1

Answer 1

is this really
\[6-2^x+\log(5)=1\]???

Answer 2

yeup!

Answer 3

you need an exact answer, or a decimal?

Answer 4

we can start with
\[5+\log(5)=2^x\]

Answer 5

erm, im not too sure. I have to type in the answer

Answer 6

by the change of base formula if \[5+\log(5)=2^x\] then
\[x=\frac{\ln(5+\log(5))}{\ln(2)}\]

Answer 7

not sure what kind of answer you are looking for
if you want a decimal look at this
http://www.wolframalpha.com/input/?i=6-2^x%2B \log%285%29%3D1&a=*FunClash.log-_*Log10-

Answer 8

well copy and paste it

Answer 9

click on "approximate form" and you will see the decimal solution about \(2.5107\)

Answer 10

oh yeah, i gots it. I think it is asking for a decimal. You are a life saver!