Find the angles Diagram below, I've found one angle on my own and need help finding the others.
|dw:1429759543021:dw|
So I got c= 10.98 DEG
How did you find that?
I used the formula
Uhm let me find it.. \[\frac{ \cos C = (a2 + b2 − c2) }{ 2ab }\]
Thos are suppose to be squared
Right - you used the cosine law. Why not just use it two more times for the other two angles? Or better yet, use it once more, then subtract the two angles you have from 180 to find the third!
I just don't know the cosine law for the other two angles >.<
It's exactly the same! Don't get stuck on the fact that a, b, and c in your equation need to correspond exactly to a, b, and c in the figure. They're just three variables. This time, set say you want to find angle a in your figure. Then a and b in your equation will be the two adjacent sides (in this case, sides b and c), and c in your equation will be the opposite side (in this case, side a).
Let me see...
hehe why did you leave the other post lol
Let me see...\[4^2+1.2^2-2(4)(1.2)Cos(B)\]
Is that right?
that equals to 3^2
how can solve without euqlity
\[\cos B=\frac{4^2+(1.2)^2-3^2}{2(4)(1.4)}\]
B=28.4579982553 repeat the same thing with other angle
don't use radians in calculator otherwise you will always get wrong answers
Wait now I'm super confused
28.4579982553 can't be right
Because 3 is VERY close to 4 and I can't see 3 being the 2nd largest and far larger than 1.2 so how does it get such a small angle?
28.46 is correct! Which makes the third angle what?
(PS. your drawing is not to scale so the angles won't necessarily match what you see in the picture)
But whattt that makes the third angle like 150 ._.
So? What's wrong with that? |dw:1429761969693:dw| ^That's what your triangle really looks like!
for me makes perfect sense the way you reasoning is off hehe if you actually draw to scale you will see that the two angles are small and one is huge the diagram provided by @matt is good to illustrate this
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