MEDALLSS if someone can give me the answer to this please and help me!The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.
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OpenStudy (anonymous):
do you know how to take the derivative
OpenStudy (anonymous):
sort of @optiquest butid rather have you show me so i can learn it for these type of problems if you dont mind!
OpenStudy (anonymous):
0th derivative is position, 1st derivative is velocity, 2nd is accelation
\[s'(t) = -9\]
OpenStudy (anonymous):
\[s'(1) = -9\]
OpenStudy (anonymous):
okay i see
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OpenStudy (anonymous):
\[f(t) = a t^n \]
\[f'(t) = (n-1) * a * t ^{n-1}\]
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
okay so would would i do now with that equation! plug in the numbers!? i just dont know what goes where now @optiquest
OpenStudy (anonymous):
(n-1) should be (n)
OpenStudy (anonymous):
nothing else to do
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OpenStudy (anonymous):
f′(t)=(n)∗a∗tn−1 okay
OpenStudy (anonymous):
so the answers f′(t)=(n)∗a∗tn−1!?
OpenStudy (anonymous):
its -9
OpenStudy (anonymous):
ohhhh okay i see how that is
OpenStudy (anonymous):
thank you :) @optiquest
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