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Mathematics 15 Online
OpenStudy (anonymous):

MEDALLSS if someone can give me the answer to this please and help me!The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.

OpenStudy (anonymous):

do you know how to take the derivative

OpenStudy (anonymous):

sort of @optiquest butid rather have you show me so i can learn it for these type of problems if you dont mind!

OpenStudy (anonymous):

0th derivative is position, 1st derivative is velocity, 2nd is accelation \[s'(t) = -9\]

OpenStudy (anonymous):

\[s'(1) = -9\]

OpenStudy (anonymous):

okay i see

OpenStudy (anonymous):

\[f(t) = a t^n \] \[f'(t) = (n-1) * a * t ^{n-1}\]

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

okay so would would i do now with that equation! plug in the numbers!? i just dont know what goes where now @optiquest

OpenStudy (anonymous):

(n-1) should be (n)

OpenStudy (anonymous):

nothing else to do

OpenStudy (anonymous):

f′(t)=(n)∗a∗tn−1 okay

OpenStudy (anonymous):

so the answers f′(t)=(n)∗a∗tn−1!?

OpenStudy (anonymous):

its -9

OpenStudy (anonymous):

ohhhh okay i see how that is

OpenStudy (anonymous):

thank you :) @optiquest

OpenStudy (anonymous):

np

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