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Laplace transform tu(t-2)
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I think it is in t*f(t) form so -d/ds*F(s)...
e^(-2s) L[g(t+2)]
L[t+2] = L[g(t+2)] it looks like from the table?
Yes. However I don't think I have dealt with g(t) before.....
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1/s + 1/s^2
g(t) means the other function in the problem, so whatever is not the step function
Thanks again!
was it right?
http://www.wolframalpha.com/input/?i=laplace+transform+t*unit+step%28t-2%29+respect+to+t 2/s not 1/s but i think thats it
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e^-2s/s^2 + 2e^-2s/s
cool
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