Question

If f(x) = log3 (x + 1), what is f^−1 (2)?

1
8
10
27

Answer 1

f(x)=y
if f has an inverse
then
f^{-1}(y)=x

so if you have f^{-1}(2)=x then f(x)=2

so solve f(x)=2 for x
that is solve log_3(x+1)=2

Answer 2

I still dont understand

Answer 3

Plug in 2 for x?
So log_3 ( 2+1 ) = 2?

Answer 4

no

Answer 5

solve for x

Answer 6

\[\log_3(x+1)=2\]

Answer 7

recall
\[3^{\log_3(a)}=a \text{ assuming } a>0\]

Answer 8

so that is
you have
\[3^{\log_3(x+1)}=3^2 \]

Answer 9

using the thought I just mentioned you have
x+1=3^2
solve for x

Answer 10

So the answer would be 8?

Answer 11

yes 9-1 is 8