How do I find out if this is an identity?
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I would rather someone explain it to me instead of reading it in a link.
just look at the link bro
it will help
Can you just walk me through it instead? (:
no i helped u wiht the link thats all u need u can read
I'm looking for someone to actually help me first-hand, not send me links.
ok what ever bro
@kkbrookly are you there?
csc(x)=1/sin(x)
you can apply this identity and say sin(x)csc(x)=1 since sin(x)/sin(x)=1 on its domain of course
then it is all up to you to apply a pythagorean identity
I'm trying to look up a list of the Pythagorean identities so I can choose one, but I can't find them.
do you know sin^2(x)+cos^2(x)=1?
this is a pythagorean identity
you can write it a couple different ways sin^2(x)=1-cos^2(x) or cos^2(x)=1-sin^2(x)
Yes, so I choose the one with sin right?
you have the left hand side is 1-sin^2(x) right?
when x isn't pi*n of course
if you want to be all crazy about it csc(x)=1/sin(x) and so the domain of 1/sin(x) is all real numbers except when x is pi*n you know where n is an integer so \[\sin(x) \frac{1}{\sin(x)} =1 \text{ when } x \neq n \pi \\ \text{ and so we have } \sin(x) \csc(x)-\sin^2(x)=\cos^2(x) \text{ is an identity for number } \\ x \neq n \pi\]
That means it's an identity then
well an identity for all real numbers excluding when x is n pi where n is an integer if x is n pi where n is an integer then it isn't an identity at those times
That makes sense. Thank you so much! Can you help me with another one?
I actually have to go sorry
That's alright! Thank you (:
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