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What is the solution set of x for the given equation?x^(3/2)-x^(1/3)+4=6
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-2, -1 2, -1 -8, -1 8, -1 2, 8
\[x ^{3/2}-x ^{1/3}+4=6\]
@campbell_st
@Abhisar
@a
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@AlexandervonHumboldt2
@dan815
I could never put ^1/3 in the equation on wolfram
I plugged in 2,8 and got 6 somehow
are you sure the 1st term isn't \[x^{\frac{2}{3}} \] its just that it makes more sense that way...
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because if the equation is \[x^{\frac{2}{3}} - x^{\frac{1}{3}} + 4 = 6\] it can be reduced to a quadratic... \[(x^{\frac{1}{3}})^2 - x^{\frac{1}{3}} - 2 = 0\]
wow you came too late
well that's ok... 2, 8 is not a solution..
yea It is not
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