Draw the major neutral organic products
I think that the first one would be|dw:1429821057712:dw|
Based on http://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/addyne1.htm under Acidity of Terminal Alkynes
Does that make sense to you?
I understand the 1st one, its the second one I don't understand. I know it'll go under an elimination, because its not a primary alkyl halide
Well, I got a different answer than you for the first one. Which one do you think is correct?
yours is, i never finished the problem
Oh, ok. I think the second one basically does the same thing as the first.
Want to try to finish it based on the same idea as the first one?
for the second one its not a primary alkyl halide, its tertiary so im unsure how to draw the product
That's true. Let me look into that.
okay thank you!
Sure. :-) Apparantly, 2º and 3º-alkyl halides undergo elimination by an E2 mechanism. But I haven't been able to figure out what that means yet.
In the context of this problem.
It's basically the same thing, you end up with |dw:1429823281379:dw|
E2 means bimolecular, where both molecules (in this case the the deprotonated alkyne and the alkylhalide) interact - opposed to an E1 mech where the Br would first leave the tertiary alkylhalide
that one is incorrect.
can you post a screen shot?
it's possible that you drew it wrong?
it wanted the starting product as well
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