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Physics 12 Online
OpenStudy (anonymous):

Is this question possible?

OpenStudy (anonymous):

Here it is:

OpenStudy (anonymous):

The magnetic field perpendicular to the plane of a single copper wire loop of diameter 20.0 cm decreases from 0.6 T to zero. The diameter of the wire is 1.3 mm. How much charge moves through the wire as a result of the changing field?

OpenStudy (anonymous):

I know how I would be able to calculate the current, which is the charge per time, but they don't give a time interval...

OpenStudy (anonymous):

Sorry I don't know. But I think you are right.

OpenStudy (anonymous):

Nobody's helped you yet?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

I think I'll just give my answer as the current over t

OpenStudy (anonymous):

Yes, I think t is needed to calculate q

OpenStudy (michele_laino):

we need to know the time needed to magnetic field, in order to decrease from 0.6 Tesla to 0 Tesla

OpenStudy (irishboy123):

i think the question is asking how much charge passes any given point during the overall field change. rate of change irrelevant. thus, note the following: \[|E| = \frac{d \phi}{dt} = IR = \frac{dQ}{dt} R\] \[dQ = \frac{d \phi}{R}\] \[Q = \frac{∆ \phi}{R}\] for resistance, R, you know its dimensions and that it is copper so: \[R = \frac{\rho l}{A}\] rho for Cu is 1.68 (10^-8) Ohm m

OpenStudy (michele_laino):

good job! @IrishBoy123

OpenStudy (michele_laino):

I have forgotten the so called law of Felici

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