A 53-N force is needed to keep a 50.0-kg box sliding across a flat surface at a constant velocity. What is the coefficient of kinetic friction between the box and the floor?0.11
a)0.10
b)0.13
c)0.09
d)0.11

Question

A 53-N force is needed to keep a 50.0-kg box sliding across a flat surface at a constant velocity. What is the coefficient of kinetic friction between the box and the floor?0.11
	a)0.10
	b)0.13
	c)0.09
        d)0.11

anonymous · Answer

Constant velocity means the net force equals zero, so the force of friction has to equal the 53 N force. The force of friction is given by (normal force)*(coefficient of friction). To find the normal force, multiply 50 by the acceleration due to gravity (either 9.8 or 10). Using 10: 50 * 10 = 500. So if 500 times the coefficient of friction equals 53, then 53 divided by 500 equals the coefficient of friction.
53/500 = .106
So i guess it's D

anonymous · Answer

thanks