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Mathematics 22 Online
OpenStudy (kkbrookly):

Can someone tell me if this is an identity or not?

OpenStudy (kkbrookly):

OpenStudy (anonymous):

To start you want to expand the first term. \[2sinx +1-2sinx+\sin^{2}x= 2-\cos^{2}x\] Next you want to remove the terms that cancel out. \[1+\sin^{2}x=2-\cos^{2}x\] Change the sine term on the left side to a cosine term. \[1+(1-\cos^{2}x)=2-\cos^{2}x\] Distribute and add. \[2-\cos^{2}x=2-\cos^{2}x\]

OpenStudy (kkbrookly):

This is so helpful! Thank you! Can you take a look at one more?

OpenStudy (kkbrookly):

@awesomelady2

OpenStudy (anonymous):

\( cos\ x~(cos\ x-sec~x)= cos^2x-1=-(1-cos^2x)=-sin^2x\) So yes. It is an identity

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